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Joe Schobert selected as AFC Defensive Player of the Week

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Cleveland linebacker honored after intercepting two passes in win over the Dolphins.

Miami Dolphins v Cleveland Browns Photo by Jamie Sabau/Getty Images

Cleveland Browns linebacker Joe Schobert was named on Wednesday as the AFC Defensive Player of the Week.

Schobert was honored for his play against the Miami Dolphins where he had five tackles, defended four passes and a pair of interceptions. It was the second consecutive game where Schobert had two interceptions, making him just the sixth linebacker in league history to have multiple interceptions in consecutive games and the first to do it since Cato June in 2005, according to clevelandbrowns.com.

The fourth-year linebacker has a team-high 97 tackles and his four interceptions ties him for fourth-best in the league. Schobert is the first Cleveland player to be selected as the AFC’s Defensive Player of the Week since 2012, when linebacker D’Qwell Jackson was honored following a five tackle day in a win over the Oakland Raiders.

According to the team’s website, this is the third time this season a Browns player has picked up a Player of the Week Award as Schobert joins punter Jamie Gillan, who was Special Teams Player of the Week in Week 2 and running back Nick Chubb, who was named Offensive Player of the Week in Week 4.

The Browns go for their fourth consecutive win on Sunday when they face the Pittsburgh Steelers at Heinz Field.