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The Cleveland Browns signed defensive tackle Jordan Elliott on Thursday. He is the fourth player of the team’s seven-person draft class to be signed.
Taken in the third round at No. 88 overall, Elliott’s contract will be worth about $4.5 million, with an $897,036 signing bonus over four years, according to OverTheCap’s pre-determined draft chart. His cap hit in 2020 will be roughly $834,259, which is far behind fellow defensive tackles Sheldon Richardson ($13.6 million), Andrew Billings ($3.5 million) and Larry Ogunjobi ($2.3 million), for those of you keeping score at home.
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— Cleveland Browns (@Browns) July 2, 2020
DT Jordan Elliott has signed his rookie contract!
» https://t.co/SHy8nsORCc pic.twitter.com/XAYFqt9L8M
Elliott, who is 6-foot-4 and 302 pounds, played in 25 career games, making 12 starts, for Missouri after transferring from Texas after his freshman year. He finished his collegiate career with 68 tackles, 5.5 sacks, a forced fumble and a blocked kick. He will wear No. 61 for the Browns.
While Elliott needs to be more consistent, the talent is there for him to succeed, The Athletic’s Dane Brugler told clevelandbrowns.com in June:
“We know talent is not a question for Jordan Elliott. There’s a plan and a method to the madness. He wakes up and gets out of bed with this kind of talent. Now, the coaches need to rein it in and get him to do this from a snap-in, snap-out basis.”
Elliott joins tight end Harrison Bryant (fourth round), center Nick Harris (fifth round) and wide receiver Donovan Peoples-Jones (sixth round) as draft picks the Browns have signed so far this offseason.