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Browns make a free agency splash with the signing of S John Johnson

Cleveland adds a top-tier safety to their defense.

Los Angeles Rams v Cleveland Browns Photo by Gregory Shamus/Getty Images

The Cleveland Browns made a big splash on the first day of the legal tampering period in the NFL, agreeing to terms with free agent safety John Johnson, formerly of the Los Angeles Rams. According to Mike Garafolo, Johnson agreed to a 3-yeal deal worth $33.75 million, including $24 million guaranteed.

Johnson was a workhorse for the Rams last season, playing every single snap for the team, which was a great sign after he had an injury-plagued 2019 season. He led the team last season with 105 tackles, 2 tackles for a loss, 1 interception, and 8 passes defended. He has elite coverage and tackles well — meaning Cleveland has turned their biggest weakness into one of their greatest strengths on defense.

As Pro Football Focus points out, the Browns’ safeties earned the worst cumulative grade in the NFL last season with a grade of 48.2. Johnson ranked 3rd in the NFL in 2020 with a grade of 85.3.

What does it mean for the Browns at safety? Garafolo says the Browns are “feeling good about a versatile safety group that includes Grant Delpit and Ronnie Harrison.” Another benefit that Johnson provides is that he is a leader and was the playcaller of the Rams’ defense last year:


How would you grade the Browns’ signing of John Johnson?

This poll is closed

  • 93%
    Perfect! Just the type of player we needed!
    (1491 votes)
  • 5%
    It’s not bad.
    (86 votes)
  • 0%
    (13 votes)
1590 votes total Vote Now