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Myles Garrett is AFC Defensive Player of the Week

Browns defense end honored after setting a franchise record with 4.5 sacks against Chicago.

NFL: Chicago Bears at Cleveland Browns Scott Galvin-USA TODAY Sports

Cleveland Browns defensive end Myles Garrett was named the AFC Defensive Player of the Week on Wednesday.

In what might be the easiest selection of the season, the NFL selected Garrett for the weekly honor after he had a franchise-record 4.5 sacks against the Chicago Bears in Sunday’s 26-6 victory.

In addition to the sacks, which broke the team’s single-game record that had been held by linebacker Andra Davis since 2003, Garrett finished with seven tackles, including four tackles for loss.

That was part of a big day from Cleveland’s defense, which totaled nine sacks of Chicago quarterback Justin Fields, and limited the Bears to 47 net yards of offense and one net passing yard, both single-game franchise records, and just one-of-11 on third downs.

This is the second time that Garrett has earned Player of the Week honors. He previously was honored in Week 4 of last season after picking up two sacks, including a key strip-sack, of Dallas quarterback Dak Prescott in Cleveland’s 49-38 win over the Cowboys.